244x^2-6x-3=0

Solution for 244x^2-6x-3=0 equation:

244x^2-6x-3=0

a = 244; b = -6; c = -3;
Δ = b2-4ac
Δ = -62-4·244·(-3)
Δ = 2964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2964}=\sqrt{4*741}=\sqrt{4}*\sqrt{741}=2\sqrt{741}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{741}}{2*244}=\frac{6-2\sqrt{741}}{488}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{741}}{2*244}=\frac{6+2\sqrt{741}}{488}
$